Question

The current through a series RL circuit, subjected to a constant emf \(\epsilon\), obeys \(L\frac{di}{dt}+iR=\epsilon\). Let L=1mH, R=1k\(\Omega\) and \(\epsilon\)=1V. The initial condition is i(0)=0. At t=1\(\mu s\), the current in mA is

• A. 1-2e^-2
• B. 1-2e^-1
• C. 1-e^-1
• D. 2-2e^-1

Answer 1

The Correct Option is C

The correct answer is (C) : 1-e^-1