>
Exams
>
Chemistry
>
Ideal gas equation
>
the correction factor a to the ideal gas equation
Question:
The correction factor ‘a’ to the ideal gas equation corresponds to
NEET (UG) - 2018
NEET (UG)
Updated On:
July 22, 2025
density of the gas molecules
electric field present between the gas molecules
volume of the gas molecules
forces of attraction between the gas molecules
Hide Solution
Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
The correct option is (D) :forces of attraction between the gas molecules.
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Ideal gas equation
In a container of volume 16.62 m$^3$ at 0°C temperature, 2 moles of oxygen, 5 moles of nitrogen and 3 moles of hydrogen are present, then the pressure in the container is (Universal gas constant = 8.31 J/mol K)
AP EAPCET - 2025
Physics
Ideal gas equation
View Solution
Avogadro’s hypothesis relates volume of gases and:
OJEE - 2024
Chemistry
Ideal gas equation
View Solution
An electric bulb of volume 300 cm$^3$ was sealed off during manufacture at a pressure of 1 mm of mercury at 27°C. The number of air molecules contained in the bulb is, (R = 8.31 J mol$^{-1}$ K$^{-1}$ and $N_A = 6.02 \times 10^{23}$)
COMEDK UGET - 2024
Physics
Ideal gas equation
View Solution
Real gas behaves like an ideal gas at:
JEECUP - 2024
Chemistry
Ideal gas equation
View Solution
The stoichiometric reaction of 516 g of dimethyldichlorosilane with water results in a tetrameric cyclic product X in 75% yield. The weight (in g) of X obtained is___. [Use, molar mass (g mol
−1
): H = 1, C = 12, O = 16, Si = 28, Cl = 35.5]
JEE Advanced - 2023
Chemistry
Ideal gas equation
View Solution
View More Questions
Questions Asked in NEET exam
An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature \(27^\circ\)C. The mass of the oxygen withdrawn from the cylinder is nearly equal to:
[Given, \(R = \frac{100}{12} \text{ J mol}^{-1} \text{K}^{-1}\), and molecular mass of \(O_2 = 32 \text{ g/mol}\), 1 atm pressure = \(1.01 \times 10^5 \text{ N/m}^2\)]
NEET (UG) - 2025
Ideal-gas equation and absolute temperature
View Solution
A wire of resistance \(R\) is cut into 8 equal pieces. From these pieces, two equivalent resistances are made by adding four of these together in parallel. Then these two are added in series. The net effective resistance of the combination is:
NEET (UG) - 2025
Resistance
View Solution
Consider the diameter of a spherical object being measured with the help of a Vernier Callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least count in the M.S. is 0.1 cm and the zero of V.S. is at -0.1 cm when the jaws of Vernier callipers are closed.
If the main scale reading for the diameter is \(M = 5\) cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is:
NEET (UG) - 2025
Measurement of length
View Solution
De-Broglie wavelength of an electron orbiting in the \(n = 2\) state of hydrogen atom is close to (Given Bohr radius = 0.052 nm):
NEET (UG) - 2025
de broglie hypothesis
View Solution
Which chromosome in the human genome has the highest number of genes?
NEET (UG) - 2025
Human genome
View Solution
View More Questions
NEET Notification
GMC Azamgarh Admission 2025: Dates, Courses, Fees, Eligibility, Select
July 22, 2025
GMC Azamgarh Admission 2025
Read More