Upon heating, \(H_3PO_3\) undergoes a disproportionation reaction to produce \(H_3PO_4 \)and \(PH_3\).
While \(H_3PO_3\) can act as a reducing agent, \(H_3PO_4\) cannot.
\(H_3PO_3\) is a monobasic acid.
The H atom of the P-H bond in \(H_3PO_3 \)is not ionizable in water.
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The Correct Option isA, B, D
Solution and Explanation
\(\begin{array}{l}4H_{3}PO_{3} \overset{\Delta }{\rightarrow}PH_{3} + 3H_{3}PO_{4}\end{array}\) In H3PO4, phosphorous is present in the highest oxidation state, i.e., +5. So H3PO4 cannot act as a reducing agent. Structure of H3PO3,
It is a dibasic acid. H atom present in the P–H bond is not ionizable. These P-H bonds are not ionisable to give H+ and do not play any role in basicity. Only those H atoms which are attached with oxygen in P-OH form are ionisable and cause the basicity. Thus, H3PO3 and H3PO4 are dibasic and tribasic, respectively as the structure of H3PO3 has two P – OH bonds and H3PO4 three.
P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.