The correct statement(s) for the following addition reactions is(are)
- $O$ and $P$ are identical molecules.
- ($M$ and $O$) and ($N$ and $P$) are two pairs diastereomers
- ($M$ and $O$) and ($N$ and $P$) are two pairs of enantiomers.
- Bromination proceeds through trans-addition in both the reactions
The Correct Option is D
Solution and Explanation
Top Questions on Hydrocarbons
Complete the following reactions by writing the structure of the main products:
- CBSE CLASS XII - 2025
- Chemistry
- Hydrocarbons
- The alkane from below having two secondary hydrogens is:
- JEE Main - 2025
- Chemistry
- Hydrocarbons
- Consider the following statements
Statement I: Benzene undergoes electrophilic substitution with excess chlorine in the presence of anhydrous AlCl$_3$
Statement - II: Benzene also undergoes electrophilic substitution with chlorine in the presence of UV light.
The correct answer is- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- An alcohol 'X' (C$_4$H$_{10}$O) reacts with conc. HCl at room temperature and gives chloride. 'X' on dehydration followed by ozonolysis gives 'Y' and 'Z'. Find 'Y' and 'Z'.
- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- The empirical formula of the compound 'D' formed in the given reaction sequence is
C₂H₄ \(\xrightarrow{Br_2|CCl_4}\) A \(\xrightarrow{(i) alc. KOH (ii) NaNH_2}\) B \(\xrightarrow{cyclic\;polymerization}\) C \(\xrightarrow{Cl_2(excess), dry\;AlCl_3, dark, cold}\) D- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
Questions Asked in JEE Advanced exam
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____.
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80- JEE Advanced - 2025
- Organic Chemistry
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
- JEE Advanced - 2025
- binomial expansion formula
- The total number of real solutions of the equation $$ \theta = \tan^{-1}(2 \tan \theta) - \frac{1}{2} \sin^{-1} \left( \frac{6 \tan \theta}{9 + \tan^2 \theta} \right) $$ is
(Here, the inverse trigonometric functions $ \sin^{-1} x $ and $ \tan^{-1} x $ assume values in $[-\frac{\pi}{2}, \frac{\pi}{2}]$ and $(-\frac{\pi}{2}, \frac{\pi}{2})$, respectively.)- JEE Advanced - 2025
- Inverse Trigonometric Functions
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
- JEE Advanced - 2025
- Coordinate Geometry
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity):
- JEE Advanced - 2025
- Waves and Oscillations
Concepts Used:
Hydrocarbons
Hydrocarbons can be described as organic compounds that consists only hydrogen and carbon atoms. These compounds are of different types and thereby have distinct natures. Hydrocarbons are colorless gases and are known for discharging faint odours. These have been categorized under four major classes named as alkynes, alkanes, alkenes, and aromatic hydrocarbons.
Types of Hydrocarbons
- Saturated hydrocarbons - Saturated hydrocarbons are those compounds where there is a single bond exists between carbon atoms and are saturated with atoms of hydrogen.
- Unsaturated hydrocarbons - Hydrocarbons comprises of at least one double or triple bond between carbon atoms are known as unsaturated hydrocarbons.
- Aliphatic hydrocarbons - The term denotes the hydrocarbons formed as an outcome of the chemical degradation of fats. Aliphatic hydrocarbons are basically chemical compounds.
- Aromatic hydrocarbons - They are distinguished because of the presence of benzene rings in them. They give away distinct types of aroma. These hydrocarbons comprises of only hydrogen and carbon atoms.