The correct stability order of the following diazonium salts is: 
Choose the correct answer from the options given below:
C $>$ A $>$ D $>$ B
Step 1: Basic stability rule for diazonium salts.
Aryl diazonium salts are stabilized by electron donating groups on the benzene ring and destabilized by strong electron withdrawing groups.
Step 2: Effect of substituents.
(A) $-OCH_3$: Strong $+M$ (electron donating) effect, stabilizes diazonium ion greatly.
(C) H: No substituent effect, moderate stability.
(D) $-CN$: Strong $-M$ effect, reduces stability.
(B) $-NO_2$: Very strong $-M$ and $-I$ effects, maximum destabilization.
Step 3: Ordering stability.
\[ \text{A (most stable)}>\text{C}>\text{D}>\text{B (least stable)} \] Step 4: Final conclusion.
The correct stability order is A $>$ C $>$ D $>$ B, corresponding to option (1).
Arrange the following carbanions in the decreasing order of stability:
I. $p$-$\mathrm{Br{-}C_6H_4{-}CH_2^-}$
II. $\mathrm{C_6H_5{-}CH_2^-}$
III. $p$-$\mathrm{CH_3O{-}C_6H_4{-}CH_2^-}$
IV. $p$-$\mathrm{CHO{-}C_6H_4{-}CH_2^-}$
V. $p$-$\mathrm{CH_3{-}C_6H_4{-}CH_2^-}$
Choose the correct answer from the options given below:
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
Consider the following two reactions A and B: 
The numerical value of [molar mass of $x$ + molar mass of $y$] is ___.
Consider an A.P. $a_1,a_2,\ldots,a_n$; $a_1>0$. If $a_2-a_1=-\dfrac{3}{4}$, $a_n=\dfrac{1}{4}a_1$, and \[ \sum_{i=1}^{n} a_i=\frac{525}{2}, \] then $\sum_{i=1}^{17} a_i$ is equal to