Question:
The correct sequence of reagents for the above conversion of X to Y is :
The correct sequence of reagents for the above conversion of X to Y is :
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Jones reagent ($CrO_3/H_2SO_4$) is a strong oxidant that will take a primary alcohol all the way to a carboxylic acid.
Updated On: Feb 4, 2026
- (i) NaOH (aq) (ii) Jones reagent (iii) H₃O⁺
- (i) NaOEt (ii) B₂H₆/H₂O₂ (iii) Jones reagent
- (i) B₂H₆/H₂O₂ (ii) NaOEt (iii) Jones reagent
- (i) Jones reagent (ii) NaOEt (iii) Hot KMnO₄/KOH
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
To convert an alkyl halide (X) to a carboxylic acid/ketone (Y) at the terminal position, one usually needs to form an alkene, perform anti-Markovnikov hydration, and then oxidize.
Step 3: Detailed Explanation:
Assuming X is an alkyl halide:
1. NaOEt: Performs dehydrohalogenation to form an alkene.
2. B₂H₆/H₂O₂, OH⁻: Hydroboration-oxidation gives the anti-Markovnikov alcohol (primary alcohol).
3. Jones reagent: Oxidizes the primary alcohol to a carboxylic acid.
This sequence allows for functional group migration and oxidation to the terminal carbon.
Step 4: Final Answer:
The sequence is (i) NaOEt (ii) B₂H₆/H₂O₂ (iii) Jones reagent.
To convert an alkyl halide (X) to a carboxylic acid/ketone (Y) at the terminal position, one usually needs to form an alkene, perform anti-Markovnikov hydration, and then oxidize.
Step 3: Detailed Explanation:
Assuming X is an alkyl halide:
1. NaOEt: Performs dehydrohalogenation to form an alkene.
2. B₂H₆/H₂O₂, OH⁻: Hydroboration-oxidation gives the anti-Markovnikov alcohol (primary alcohol).
3. Jones reagent: Oxidizes the primary alcohol to a carboxylic acid.
This sequence allows for functional group migration and oxidation to the terminal carbon.
Step 4: Final Answer:
The sequence is (i) NaOEt (ii) B₂H₆/H₂O₂ (iii) Jones reagent.
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