>
Exams
>
Physics
>
Gravitation
>
the correct relation between kinetic energy k e an
Question:
The correct relation between kinetic energy (K.E) and total energy (T.E) of a satellite orbiting around the planet is
JEE Main
Updated On:
Apr 6, 2024
$K.E = |T.E| $
$ K.E = 2|T.E|$
$K.E = \frac{|T.E|} 2 $
$ |T.E|=3K.E$
Hide Solution
Verified By Collegedunia
The Correct Option is
A
Solution and Explanation
The Correct answer is option is (A) : $K.E = |T.E| $
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Gravitation
The gravitational field at a point in space is:
CUET (PG) - 2025
Physics
Gravitation
View Solution
Two satellites A and B go around a planet in circular orbits having radii of 4R and R, respectively. If the velocity of satellite A is 3v, the velocity of satellite B will be:
CUET (PG) - 2025
Atmospheric Science
Gravitation
View Solution
The period of a satellite in a circular orbit of radius 12000 km around a planet is 3 hours. Obtain the period of a satellite in a circular orbit of radius 48000 km around the same planet.
CUET (PG) - 2025
Atmospheric Science
Gravitation
View Solution
The escape velocity from the surface of a planet is \(v_e\). What will be the escape velocity from a planet whose mass and radius are twice that of the original planet?
BITSAT - 2025
Physics
Gravitation
View Solution
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : The radius vector from the Sun to a planet sweeps out equal areas in equal intervals of time and thus areal velocity of planet is constant.
Reason (R) : For a central force field the angular momentum is a constant. In the light of the above statements, choose the most appropriate answer from the options given below :
JEE Main - 2025
Physics
Gravitation
View Solution
View More Questions
Questions Asked in JEE Main exam
Total number of non-bonded electrons present in \( \text{NO}_2 \); ion based on Lewis theory is:
JEE Main - 2025
Chemical bonding and molecular structure
View Solution
Match List - I with List - II.
JEE Main - 2025
Thermodynamics
View Solution
The variance of the numbers 8, 21, 34, 47, \dots, 320, is:
JEE Main - 2025
Arithmetic Progression and Variance
View Solution
The value of \( (\sin 70^\circ)(\cot 10^\circ \cot 70^\circ - 1) \) is:
JEE Main - 2025
Trigonometric Identities
View Solution
Let A and B be the two points of intersection of the line \( y + 5 = 0 \) and the mirror image of the parabola \( y^2 = 4x \) with respect to the line \( x + y + 4 = 0 \). If \( d \) denotes the distance between A and B, and \( a \) denotes the area of \( \Delta SAB \), where \( S \) is the focus of the parabola \( y^2 = 4x \), then the value of \( (a + d) \) is:
JEE Main - 2025
Angle between a Line and a Plane
View Solution
View More Questions