Ne<Xe>Li>K<Cs
Xe<Li<K<Cs<Ne
Cs>K>Li>Xe>Ne
Li>K>Cs>Ne>Xe
Ne>Xe>Li>K>Cs
Ionization enthalpy trends:
Correct order: Ne > Xe > Li > K > Cs
Thus, the correct option is (E): \( \text{Ne} > \text{Xe} > \text{Li} > \text{K} > \text{Cs} \).
List-I | List-II | ||
(A) | mI | (I) | Shape of orbital |
(B) | ms | (II) | Size of orbital |
(C) | I | (III) | Orientation of orbital |
(D) | n | (IV) | Orientation of spin of electron |
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: