Question:
The correct order of the $O - O$ bond length in $O_2,H_2 O_2 $ and $O_3 $ is
The correct order of the $O - O$ bond length in $O_2,H_2 O_2 $ and $O_3 $ is
Updated On: Jul 13, 2024
- $O_2 > O_3 > H_2O_2$
- $O_3 > H_2O_2 > O_2 $
- $O_2 > H_2O_2 >O_3$
- $H_2O_2 > O_3 > O_2 $
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The bond length of $O -O$ in $H_2O_2$ is $147.5 \: pm$, in $O_3$ is $128 \: pm$ and in $O_2$ it is $121\: pm$, so the correct order is $ O_2 < O_3 < H_2O_2.$
Was this answer helpful?
0
0
Top Questions on Molecular Orbital Theory
- In \( \text{O}_2^- \), \( \text{O}_2 \), and \( \text{O}_2^{2-} \) molecular species, the total number of antibonding electrons respectively are:
- MHT CET - 2024
- Chemistry
- Molecular Orbital Theory
The total number of molecular orbitals formed from 2s and 2p atomic orbitals of a diatomic molecule is _________.
- JEE Main - 2024
- Chemistry
- Molecular Orbital Theory
- Given below are two statements:
Statement (I): A \(\pi\) bonding MO has lower electron density above and below the inter-nuclear axis.
Statement (II): The \(\pi^*\) antibonding MO has a node between the nuclei.
In the light of the above statements, choose the most appropriate answer from the options given below:- JEE Main - 2024
- Chemistry
- Molecular Orbital Theory
- The maximum number of orbitals which can be identified with \( n = 4 \) and \( m_l = 0 \) is ______
- JEE Main - 2024
- Chemistry
- Molecular Orbital Theory
- Number of molecules having bond order 2 from the following molecule is ...................
$C_2, O_2, Be_2, Li_2, Ne_2, N_2, He_2$- JEE Main - 2024
- Chemistry
- Molecular Orbital Theory
View More Questions
Questions Asked in NEET exam
- \(^{290}_{82}X\stackrel{\alpha}{\rightarrow}Y\stackrel{e^+}{\rightarrow}Z\stackrel{\beta^-}{\rightarrow}P\stackrel{e^-}{\rightarrow}Q\)
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :- NEET (UG) - 2024
- Nuclear physics
- In a plant, black seed color (BB/Bb) is dominant over white seed color (bb). In order to find out the genotype of the black seed plant, with which of the following genotype will you cross it?
- NEET (UG) - 2024
- monohybrid cross
- Given below are two statements:
Statement I: Both [Co(NH3)6]3+ and [CoF6]3- complexes are octahedral but differ in their magnetic behaviour.
Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3- is paramagnetic.
In the light of the above statements, choose the correct answer from the options given below:- NEET (UG) - 2024
- Electronic configuration of atoms and ions
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector \(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :- NEET (UG) - 2024
- Magnetic Field
- Choose the correct circuit which can achieve the bridge balance.
- NEET (UG) - 2024
- Digital Electronics and Logic Gates
View More Questions
Concepts Used:
Molecular Orbital Theory
The Molecular Orbital Theory is a more sophisticated model of chemical bonding where new molecular orbitals are generated using a mathematical process called Linear Combination of Atomic Orbitals (LCAO).
Molecular Orbital theory is a chemical bonding theory that states that individual atoms combine together to form molecular orbitals. Due to this arrangement in MOT Theory, electrons associated with different nuclei can be found in different atomic orbitals. In molecular orbital theory, the electrons present in a molecule are not assigned to individual chemical bonds between the atoms. Rather, they are treated as moving under the influence of the atomic nuclei in the entire molecule.
