To determine the correct order of energy levels for the d orbitals in a square planar complex, it is important to understand the geometry and electron configuration involved.
Square planar complexes are typically formed by d8 metal ions. In such complexes, there is a distinct splitting of the d orbitals due to the ligand field effect.
The splitting pattern of d orbitals in a square planar complex is primarily influenced by both the nature of ligands and the metal center. However, the typical energy order of the d orbitals when influenced by the ligand field is:
Therefore, the order of increasing energy is:
\(d_{xz}=d_{yz}<d_{z^2}<d_{xy}<d_{x^2-y^2}\)
This matches the correct answer: \(d_{xz}=d_{yz}<d_{z^2}<d_{xy}<d_{x^2-y^2}\).
All other options do not correctly represent the energy ordering of d orbitals in a square planar complex, validating our correct option choice. For example:
Among, Sc, Mn, Co and Cu, identify the element with highest enthalpy of atomisation. The spin only magnetic moment value of that element in its +2 oxidation state is _______BM (in nearest integer).
Given below are two statements :
Statement I : CrO\( _3 \) is a stronger oxidizing agent than MoO\( _3 \)
Statement II : Cr(VI) is more stable than Mo(VI) In the light of the above statements, choose the correct answer from the options given below
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