Question

The correct order of reducing power of alkali metals in aqueous solution is

• A. \( \text{Li} > \text{Rb} > \text{K} > \text{Na} \)
• B. \( \text{Li} > \text{Na} > \text{K} > \text{Rb} \)
• C. \( \text{Rb} > \text{K} > \text{Na} > \text{Li} \)
• D. \( \text{Rb} > \text{Na}> \text{K} > \text{Li} \)

Hint:

The reducing power of alkali metals increases as the atomic size increases down the group, due to the ease of losing electrons.

Answer 1

The Correct Option is A

The reducing power of alkali metals increases as we move down the group. Therefore, the correct order of reducing power is: \[ \text{Li} > \text{Rb} > \text{K} > \text{Na} \] This order is because lithium has the highest ionization energy and hence the greatest ability to reduce other substances.