Question:

The correct order of energy levels of the molecular orbitals of N2 is

Updated On: Nov 14, 2025
  • g<1σu<2σg<2σu<1πu<3σg<1πg<3σu
  • g<1σu<2σg<2σu<3σu<3σu<1πu<1πg
  • g<1σu<2σg<2σu<1πg<3σg<1πu<3σu
  • g<1σu<2σg<2σu<3σg<1πu<1πg<3σu
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The molecular orbital configuration of nitrogen molecule (N2) can be determined using the principles of molecular orbital theory. The energy levels of molecular orbitals are essential to understand how electrons are distributed within a molecule, which further explains the chemical bonding and properties of the molecule. 

For diatomic molecules, particularly those of homonuclear diatomic molecules like N2, the energy order of molecular orbitals slightly varies as we move from lighter to heavier elements across the second period of the periodic table.

For N2 (which has a total of 14 electrons), the correct energy level order of the molecular orbitals for the ground state configuration of N2 is as follows:

  1. g - The lowest energy molecular orbital formed by the combination of 1s atomic orbitals.
  2. u - The next higher energy level due to antibonding interaction of 1s atomic orbitals.
  3. g - Formed by the combination of 2s atomic orbitals.
  4. u - Antibonding molecular orbital formed from 2s atomic orbitals.
  5. u - Degenerate molecular orbitals formed by the side-on overlap of 2p orbitals, has lower energy compared to 3σg for N2.
  6. g - Formed by the head-on overlap of 2pz orbitals.
  7. g - Antibonding orbitals formed from the 2p orbitals.
  8. u - The highest energy orbital (antibonding) of this sequence formed by 2p orbitals.

Therefore, the correct order of energy levels is:

g<1σu<2σg<2σu<1πu<3σg<1πg<3σu

This sequence explains why N2 has a triple bond, leading to its high bond energy and stability.

Ruling out other options requires understanding of the switch in the order of \(1π_{\text{u}}\) and \(3σ_{\text{g}}\) after going past N2, as the molecular orbital order differs for O2 and beyond.

Was this answer helpful?
0
0