Step 1: Recall the trend of electronegativity in the periodic table.
Electronegativity increases across a period (left to right) and decreases down a group (top to bottom). This means that within the second period, the electronegativity increases as we move from \( C \) to \( F \).
Step 2: Arrange the elements based on their positions in the periodic table.
Since electronegativity increases from left to right, the correct order is:
\[ C < N < O < F. \]
Final Answer: The correct order of electronegativity is \( \mathbf{C < N < O < F} \), which corresponds to option \( \mathbf{(3)} \).
Given below are two statements:
Statement I: $ H_2Se $ is more acidic than $ H_2Te $
Statement II: $ H_2Se $ has higher bond enthalpy for dissociation than $ H_2Te $
In the light of the above statements, choose the correct answer from the options given below.