Step 1: Recall the trend of electronegativity in the periodic table.
Electronegativity increases across a period (left to right) and decreases down a group (top to bottom). This means that within the second period, the electronegativity increases as we move from \( C \) to \( F \).
Step 2: Arrange the elements based on their positions in the periodic table.
Since electronegativity increases from left to right, the correct order is:
\[ C < N < O < F. \]
Final Answer: The correct order of electronegativity is \( \mathbf{C < N < O < F} \), which corresponds to option \( \mathbf{(3)} \).
The correct orders among the following are:
[A.] Atomic radius : \(B<Al<Ga<In<Tl\)
[B.] Electronegativity : \(Al<Ga<In<Tl<B\)
[C.] Density : \(Tl<In<Ga<Al<B\)
[D.] 1st Ionisation Energy :
In\(<Al<Ga<Tl<B\)
Choose the correct answer from the options given below :
Given below are two statements:
Statement I: $ H_2Se $ is more acidic than $ H_2Te $
Statement II: $ H_2Se $ has higher bond enthalpy for dissociation than $ H_2Te $
In the light of the above statements, choose the correct answer from the options given below.