Question:

The correct order of decreasing second ionisation enthalpy of Ti(22), V(23), Cr(24) and Mn(25) is

Updated On: May 1, 2024
  • Cr > Mn > V > Ti
  • V > Mn > Cr > Ti
  • Mn > Cr > Ti > V
  • Ti > V > Cr > Mn
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The Correct Option is A

Solution and Explanation

The amount of energy required to remove an
electron from unipositive ion is referred as second
ionisation potential.
In Ti, V, Cr and Mn, generally second ionisation
energy increases with increase in atomic number
but second ionisation potential of Cr is greater than
that of Mn due to the presence of exactly half-filled
d-subshell in Cr.
Thus, the order of second ionisation enthalpy is
$\hspace20mm $Cr > Mn > V > Ti
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Concepts Used:

D and F Block Elements

The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements. 

They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.

Read More: The d and f block elements