Question

The correct increasing order of boiling points of the following compounds is

• A. $CH_2Br_2 < CH_3Br < CHBr, < CH_3Cl $
• B. $CH_3Cl < CH_3Br < CH_2Br_2 < CHBr_3 $
• C. $CH_2Br_2 < CHBr_3 < CH_3Br < CH_3CH $
• D. $ CH_3Cl < CHBr_3 < CH_3Br < CH_2Br_2 $
• E. $CHBг_3 < CH_2Br_2 < CH_3Br < CH_3CI $

Answer 1

The Correct Option is B

The boiling point of a compound depends on factors such as molecular weight, polarity, and the presence of halogen atoms. In general, the boiling point increases with increasing molecular weight and polarizability.

Let's analyze the given compounds:

• CH₃Cl: Methyl chloride is a small molecule with one chlorine atom, resulting in a relatively low boiling point.
• CH₃Br: Methyl bromide contains a larger bromine atom, leading to stronger van der Waals forces and a slightly higher boiling point than CH₃Cl.
• CH₂Br₂: Dibromomethane has two bromine atoms, increasing its molecular weight and boiling point further.
• CHBr₃: Tribromomethane has three bromine atoms, making it the heaviest and most polarizable of the series, with the highest boiling point.

Therefore, the increasing order of boiling points is:

CH₃Cl < CH₃Br < CH₂Br₂ < CHBr₃

Correct Answer:

Correct Answer: (B) CH₃Cl < CH₃Br < CH₂Br₂ < CHBr₃