Question:
The corner points of feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px + qy where p, q > 0. The condition on p and q so that, minimum of Z occurs at (3, 0) and (1, 1) is :
The corner points of feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px + qy where p, q > 0. The condition on p and q so that, minimum of Z occurs at (3, 0) and (1, 1) is :
Updated On: Jun 13, 2024
- p = 2q
- \(p=\frac{q}{2}\)
- p = 3q
- p = q
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The Correct Option is B
Solution and Explanation
The correct option is (B) :\(p=\frac{q}{2}\).
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