Question:
The coordination number of $Sr^{2+}$ ion in $SrF_2$, if ionic radii are r $(Si^{2+})$ = 113 pm and r $(F^-)$ = 136 pm; is
The coordination number of $Sr^{2+}$ ion in $SrF_2$, if ionic radii are r $(Si^{2+})$ = 113 pm and r $(F^-)$ = 136 pm; is
Updated On: Jul 7, 2022
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The Correct Option is B
Solution and Explanation
Radius ratio $ = \frac{r^+}{r^-} = \frac{113}{136}$
$ = 0.830 > 0.732$.
The coordination number of $Sr^{2+}$ is $8$.
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Properties of Solids
Properties of Solids:
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