Question:

The coordinates of the vertex of the parabola \[ y = 2x^2 - 12x + 26 \] are

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For a quadratic equation \( y = ax^2 + bx + c \), use \( x = -\frac{b}{2a} \) to find the vertex.
Updated On: Mar 6, 2025
  • \( (6,13) \)
  • \( (3,-8) \)
  • \( (3,8) \)
  • \( (6,-13) \)
  • \( (3,11) \)
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The Correct Option is C

Solution and Explanation

The standard form of a quadratic equation is: \[ y = ax^2 + bx + c \] where \( a = 2 \), \( b = -12 \), and \( c = 26 \). The formula for the vertex is: \[ x = -\frac{b}{2a} \] \[ x = -\frac{-12}{2(2)} = \frac{12}{4} = 3 \] Now, substituting \( x = 3 \) in the given equation: \[ y = 2(3)^2 - 12(3) + 26 \] \[ y = 2(9) - 36 + 26 = 18 - 36 + 26 = 8 \] Thus, the vertex is \( (3,8) \). 
Final Answer: \[ \boxed{(3,8)} \]

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