The conversion of X to Y is:
Step 1: Conversion of Benzamide to X
The first step involves the reaction of benzamide (\(\text{C}_6\text{H}_5\text{CONH}_2\)) with bromine in sodium hydroxide (Br}_2/\text{NaOH}), which leads to the formation of aniline (\(\text{C}_6\text{H}_5\text{NH}_2\)) via the Hoffmann bromamide degradation reaction: \[ \text{C}_6\text{H}_5\text{CONH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{C}_6\text{H}_5\text{NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O} \] Step 2: Conversion of X to Y (Carbylamine Reaction)
The second step involves the reaction of aniline (\(\text{C}_6\text{H}_5\text{NH}_2\)) with chloroform (CHCl}_3) and alcoholic potassium hydroxide (\(\text{alc. KOH}\)). This reaction is called the Carbylamine reaction, and it produces phenyl isocyanide (\(\text{C}_6\text{H}_5\text{NC}\)) with a foul odor: \[ \text{C}_6\text{H}_5\text{NH}_2 + \text{CHCl}_3 + 3\text{KOH} \rightarrow \text{C}_6\text{H}_5\text{NC} + 3\text{KCl} + 3\text{H}_2\text{O} \] Step 3: Analysis of the Given Options
- Hoffmann Reaction: - This reaction converts amide to amine using Br}_2/\text{NaOH}, which forms aniline (X). However, the complete transformation to phenyl isocyanide (Y) is not due to Hoffmann degradation. - Etard Reaction: - The Etard reaction is used to oxidize toluene to benzaldehyde, which is unrelated to this transformation. - Stephen Reaction: - This reaction reduces nitriles to aldehydes in the presence of SnCl}_2/HCl, which is also unrelated here. - Carbylamine Reaction: - This is the correct reaction responsible for converting aniline to phenyl isocyanide, which matches the given conversion.
Final Answer:
The correct answer is (4) Carbylamine reaction, as it correctly explains the transformation of aniline (\(X\)) to phenyl isocyanide (\(Y\)).
The incorrect statement about 'B' is:
Consider the following reactions:
Y and Z respectively are:
Consider the reactions: