Question:
In the following reaction, $C_6H_5CH_2Br \ce{->[{(i) \text{Mg,Ether}}][{(ii) H_3O^+}] X }$ the product ' $X$ ' is
In the following reaction, $C_6H_5CH_2Br \ce{->[{(i) \text{Mg,Ether}}][{(ii) H_3O^+}] X }$ the product ' $X$ ' is
Updated On: Apr 26, 2024
- $C _{6} H _{5} CH _{2} OCH _{2} C _{6} H _{5}$
- $C _{6} H _{5} CH _{2} OH$
- $C _{6} H _{5} CH _{3}$
- $C _{6} H _{5} CH _{2} CH _{2} C _{6} H _{5}$
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The Correct Option is C
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Concepts Used:
Preparation of Haloalkanes
- Preparation by Alcohols: By using alcohol, we can very easily prepare Haloalkane as when R-OH is reacted with a suitable reagent it will form R-X. The following reagents will help in the formation of the reactions:
- Halogen Acids (HX)
- Thionyl chloride (SOCl2)
- Phosphorous halides (PX5 or PX3)
- Preparation by Free Radical Halogenation: The formation of alkyl bromides and alkyl chloride is very much possible with the help of free radical halogenation, but as these radicals are highly reactive and non-specific in nature, they can result in the formation of a mixture of products. Though, it's not a preferred method for the preparation of haloalkanes. For example, free radical chlorination can result in the formation of a number of haloalkanes, which in turn makes it difficult to set apart a single product.
- Preparation by Alkenes: An electrophilic addition reaction can be used to transform an alkene into a haloalkane as alkene will react with HX to form R-X.
Read More: Haloalkanes and Haloarenes