Original statement: "If the number is not divisible by 3, then it is not divisible by 15"
In logical form:
Let \( P \): "divisible by 3", \( Q \): "divisible by 15"
Statement: \( \neg P \rightarrow \neg Q \)
Contrapositive rule:
The contrapositive of \( A \rightarrow B \) is \( \neg B \rightarrow \neg A \)
Thus, contrapositive of \( \neg P \rightarrow \neg Q \) is \( Q \rightarrow P \)
Translated back:
"If the number is divisible by 15 (\( Q \)), then it is divisible by 3 (\( P \))"
Correct option: (D)
Let \( P \) be the statement "the number is not divisible by 3" and \( Q \) be the statement "the number is not divisible by 15".
The original statement is "If \( P \), then \( Q \)". The contrapositive of this statement is "If not \( Q \), then not \( P \)".
In words:
Therefore, the correct answer is (D).
For the clock shown in the figure, if
O = O Q S Z P R T, and
X = X Z P W Y O Q,
then which one among the given options is most appropriate for P?
A bag contains Violet (V), Yellow (Y), Red (R), and Green (G) balls. On counting them, the following results are obtained:
(i) The sum of Yellow balls and twice the number of Violet balls is 50.
(ii) The sum of Violet and Green balls is 50.
(iii) The sum of Yellow and Red balls is 50.
(iv) The sum of Violet and twice the number of Red balls is 50.
Which one of the following Pie charts correctly represents the balls in the bag?
In the context of the given figure, which one of the following options correctly represents the entries in the blocks labelled (i), (ii), (iii), and (iv), respectively?
If $ X = A \times B $, $ A = \begin{bmatrix} 1 & 2 \\-1 & 1 \end{bmatrix} $, $ B = \begin{bmatrix} 3 & 6 \\5 & 7 \end{bmatrix} $, find $ x_1 + x_2 $.