Question:

The constant term in the expansion of \( \left( x^3 + \frac{1}{x^2} \right)^{10} \) is:

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To find the constant term in a binomial expansion, solve for \( k \) where the exponent of \( x \) becomes zero.
Updated On: Mar 10, 2025
  • 210
  • 240
  • 140
  • 120
  • 320
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The Correct Option is A

Solution and Explanation

Using the binomial expansion formula, the general term is: \[ T_k = \binom{10}{k} (x^3)^{10-k} \left( \frac{1}{x^2} \right)^k \] \[ = \binom{10}{k} x^{3(10-k)} x^{-2k} \] \[ = \binom{10}{k} x^{30 - 5k} \] For the constant term, set \( 30 - 5k = 0 \): \[ 5k = 30 \implies k = 6 \] Substituting \( k = 6 \): \[ T_6 = \binom{10}{6} = 210 \] Thus, the constant term is 210.
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