Question:
The condition for maximum power transmission by an open belt drive considering centrifugal tension is:
(T = max. tension, \( T_C \) = centrifugal tension)
The condition for maximum power transmission by an open belt drive considering centrifugal tension is:
(T = max. tension, \( T_C \) = centrifugal tension)
(T = max. tension, \( T_C \) = centrifugal tension)
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For maximum power in a belt drive, always remember: \textbf{Maximum tension = 3 × centrifugal tension}.
Updated On: Jun 21, 2025
- \( T = 2T_C \)
- \( T = 4T_C \)
- \( T = 3T_C \)
- \( T = 3T_C^2 \)
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The Correct Option is C
Solution and Explanation
For maximum power transmission in an open belt drive, the centrifugal tension \( T_C \) must be considered.
The total tension in the belt is given as \( T \), and the power transmitted is maximum when the belt tension is three times the centrifugal tension.
This condition is derived from the relation: \[ T = T_1 + T_2 = 3T_C \] where \( T_1 \) is the tension on the tight side and \( T_2 \) is the tension on the slack side of the belt.
Hence, the condition for maximum power transmission is: \[ \boxed{T = 3T_C} \]
The total tension in the belt is given as \( T \), and the power transmitted is maximum when the belt tension is three times the centrifugal tension.
This condition is derived from the relation: \[ T = T_1 + T_2 = 3T_C \] where \( T_1 \) is the tension on the tight side and \( T_2 \) is the tension on the slack side of the belt.
Hence, the condition for maximum power transmission is: \[ \boxed{T = 3T_C} \]
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