For irrotational flow, the vorticity ($\vec{\omega}$) must be zero: \[ \vec{\omega} = \nabla \times \vec{v} = 0. \] In three-dimensional flow, this condition implies that each component of vorticity must vanish. For the specific component: \[ \omega_z = \frac{\partial v}{\partial y} - \frac{\partial w}{\partial x} = 0. \] Thus, for irrotational flow: \[ \frac{\partial v}{\partial y} = \frac{\partial w}{\partial x}. \]
In photoelectric effect, the stopping potential \( V_0 \) vs frequency \( \nu \) curve is plotted. \( h \) is the Planck's constant and \( \phi_0 \) is the work function of metal.
(A) \( V_0 \) vs \( \nu \) is linear.
(B) The slope of \( V_0 \) vs \( \nu \) curve is \( \frac{\phi_0}{h} \).
(C) \( h \) constant is related to the slope of \( V_0 \) vs \( \nu \) line.
(D) The value of electric charge of electron is not required to determine \( h \) using the \( V_0 \) vs \( \nu \) curve.
(E) The work function can be estimated without knowing the value of \( h \). \text{Choose the correct answer from the options given below:}
N equally spaced charges each of value \( q \) are placed on a circle of radius \( R \). The circle rotates about its axis with an angular velocity \( \omega \) as shown in the figure. A bigger Amperian loop \( B \) encloses the whole circle, whereas a smaller Amperian loop \( A \) encloses a small segment. The difference between enclosed currents, \( I_B - I_A \) for the given Amperian loops is:
LIST I (Plant) | LIST II (Active Principle) | ||
---|---|---|---|
A | Oleander | I | Nerin |
B | Betel Nut | II | Arecoline |
C | Aconite | III | Pseudaconitine |
D | Tobacco | IV | Nicotine |
LIST I (Branches) | LIST II (Study area) | ||
---|---|---|---|
A | Podogram | I | Footprints |
B | Cheiloscopy | II | Fingerprints |
C | Palatoscopy | III | Lip prints |
D | Dactylography | IV | Palatal rugae |
List I (\(\text{African\ Novels}\)) | List II (\(\text{Authors}\)) |
A. Things Fall Apart | I. Chimamanda Ngozi Adichie |
B. Petals of Blood | II. Tayeb Salih |
C. Season of Migration to the North | III. Ngũgĩ wa Thiong’o |
D. Half of a Yellow Sun | IV. Chinua Achebe |
Match List I with List II:
List I | List II |
---|---|
A. Spinal poison | I. Carbon monoxide |
B. NH2- | II. Linear |
C. NH4+ | III. Tetrahedral |
D. [PtCl4]- | IV. Square planar |
Choose the correct answer from the options given below: