The compressibility factor of an ideal gas is
- 1
- 2
- 4
- 6
The Correct Option is A
Solution and Explanation
$Z=\frac{P V}{(P V) \text { ideal }}=\frac{P V}{n R T}$
for non ideal gases, $ Z \neq 1$
for ideal gases. $Z=1$
Top Questions on Van Der Waals equation
- Molar volume ($ V_m $) of a van der Waals gas can be calculated by expressing the van der Waals equation as a cubic equation with $ V_m $ as the variable. The ratio (in mol dm$^{-3}$) of the coefficient of $ V_m^2 $ to the coefficient of $ V_m $ for a gas having van der Waals constants $ a = 6.0 \, \text{dm}^6 \, \text{atm mol}^{-2} $ and $ b = 0.060 \, \text{dm}^3 \, \text{mol}^{-1} $ at 300 K and 300 atm is ____. Use: Universal gas constant $ R = 0.082 \, \text{dm}^3 \, \text{atm mol}^{-1} \, \text{K}^{-1} $
- JEE Advanced - 2025
- Chemistry
- Van Der Waals equation
- Arrange the following gases in increasing order of van der Waals constant 'a'
A. Ar
B. CH4
C. H₂O
D. C6H6
Choose the correct option from the following.- JEE Main - 2023
- Chemistry
- Van Der Waals equation
- Which of the following statemnt is incorect for physisorption?
- GUJCET - 2023
- Chemistry
- Van Der Waals equation
- At low pressure, the van der Waal's equation is reduced to
- VITEEE - 2019
- Chemistry
- Van Der Waals equation
- If $V$ is the volume of one molecule of gas under given conditions, the van der Waal?s constant $b$ is
- BITSAT - 2018
- Chemistry
- Van Der Waals equation
Questions Asked in JEE Advanced exam
- Let $ x_0 $ be the real number such that $ e^{x_0} + x_0 = 0 $. For a given real number $ \alpha $, define $$ g(x) = \frac{3xe^x + 3x - \alpha e^x - \alpha x}{3(e^x + 1)} $$ for all real numbers $ x $. Then which one of the following statements is TRUE?
- JEE Advanced - 2025
- Fundamental Theorem of Calculus
- At 25$^\circ$C, the concentration of H$^+$ ions in $ 1.00 \times 10^{-3} \, \text{M} $ aqueous solution of a weak monobasic acid having acid dissociation constant $ K_a = 4.00 \times 10^{-11} $ is $ X \times 10^{-7} \, \text{M} $. The value of $ X $ is ____. {Use: Ionic product of water $ K_w = 1.00 \times 10^{-14} $ at 25$^\circ$C
- JEE Advanced - 2025
- Ionic Equilibrium
- Consider the vectors $$ \vec{x} = \hat{i} + 2\hat{j} + 3\hat{k},\quad \vec{y} = 2\hat{i} + 3\hat{j} + \hat{k},\quad \vec{z} = 3\hat{i} + \hat{j} + 2\hat{k}. $$ For two distinct positive real numbers $ \alpha $ and $ \beta $, define $$ \vec{X} = \alpha \vec{x} + \beta \vec{y} - \vec{z},\quad \vec{Y} = \alpha \vec{y} + \beta \vec{z} - \vec{x},\quad \vec{Z} = \alpha \vec{z} + \beta \vec{x} - \vec{y}. $$ If the vectors $ \vec{X}, \vec{Y}, \vec{Z} $ lie in a plane, then the value of $ \alpha + \beta - 3 $ is ________.
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct:
- JEE Advanced - 2025
- Ray optics and optical instruments
- Let $$ \alpha = \frac{1}{\sin 60^\circ \sin 61^\circ} + \frac{1}{\sin 62^\circ \sin 63^\circ} + \cdots + \frac{1}{\sin 118^\circ \sin 119^\circ}. $$ Then the value of $$ \left( \frac{\csc 1^\circ}{\alpha} \right)^2 $$ is \rule{1cm}{0.15mm}.
- JEE Advanced - 2025
- Some Applications of Trigonometry
JEE Advanced Notification
Concepts Used:
Van Der Waals Equation
Van der Waals equation is an equation relating the relationship between the pressure, volume, temperature, and amount of real gases.
Read More: Derivation of Van Der Waals Equation
Derivation of Van der Waals equation:
For a real gas containing ‘n’ moles, the equation is written as
Where, P, V, T, n are the pressure, volume, temperature and moles of the gas. ‘a’ and ‘b’ constants specific to each gas.
Where,
Vm: molar volume of the gas
R: universal gas constant
T: temperature
P: pressure
V: volume
Thus, Van der Waals equation can be reduced to ideal gas law as PVm = RT.
The equation can further be written as;
- Cube power of volume:
- Reduced equation (Law of corresponding states) in terms of critical constants:
Units of Van der Waals equation Constants
a: atm lit² mol-²
b: litre mol-¹