Question:
The complex(es), which can exhibit the type of isomerism shown by [Pt(NH3)2Br2], is(are) [en = H2NCH2CH2NH2]
The complex(es), which can exhibit the type of isomerism shown by [Pt(NH3)2Br2], is(are) [en = H2NCH2CH2NH2]
Updated On: June 02, 2025
- [Pt(en)(SCN)2]
- [Zn(NH3)2Cl2]
- [Zn(NH3)2Cl2]
- [Cr(en)2(H2O)(SO4)]+
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The Correct Option is C, D
Solution and Explanation
Isomerism is when compounds have the same chemical formula but different structural arrangements. The complex [Pt(NH3)2Br2] can show geometric isomerism due to different possibilities in the arrangement of ligands around the central metal atom. Generally, square planar and octahedral complexes are capable of exhibiting such isomerism.
We now analyze each option:
- [Pt(en)(SCN)2]: This is not the correct structure for exhibiting geometric isomerism similar to [Pt(NH3)2Br2], as it involves bidentate ligands.
- [Zn(NH3)2Cl2]: Zinc(II) complexes are often tetrahedral or square planar. With two identical ligands and two identical counter ions, this complex can potentially exhibit geometric isomerism.
- [Cr(en)2(H2O)(SO4)]+: In this complex with chromium(III) and bidentate en ligands, along with a water molecule and sulfate ion, it can show both geometric and optical isomerism.
Thus, the complexes that can exhibit geometric isomerism similar to [Pt(NH3)2Br2] are:
- [Zn(NH3)2Cl2]
- [Cr(en)2(H2O)(SO4)]+
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Concepts Used:
Inorganic chemistry
Inorganic chemistry is a branch of chemistry that deals with the study of the properties and behavior of inorganic compounds, which are substances that do not contain carbon-hydrogen (C-H) bonds. Inorganic compounds encompass a vast range of substances, including minerals, metals, nonmetals, and their compounds.