Question:

The coefficient of $x^7$ in the expansion of $(1- x - x^2 + x^3 )^6$ is

Updated On: Jul 5, 2022
  • -132
  • -144
  • 132
  • 144
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The Correct Option is B

Solution and Explanation

$(1 - x - x^2 + x^3)^6 = [(1- x) - x^2 (1 - x)]^6$ $ = (1- x)^6 (1 - x^2)^6$ $= (1 - 6x + 15x^2 - 20x^3 + 15x^4 - 6x^5 + x^6)$ $ \times (1 - 6x^2 + 15x^4 - 20x^6 + 15x^8 - 6x^{10} + x^{12})$ Coefficient of $x^7 = (- 6) (- 20) + (- 20)(15) + (- 6) (-6) = - 144$
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Concepts Used:

Binomial Theorem

The binomial theorem formula is used in the expansion of any power of a binomial in the form of a series. The binomial theorem formula is 

Properties of Binomial Theorem

  • The number of coefficients in the binomial expansion of (x + y)n is equal to (n + 1).
  • There are (n+1) terms in the expansion of (x+y)n.
  • The first and the last terms are xn and yn respectively.
  • From the beginning of the expansion, the powers of x, decrease from n up to 0, and the powers of a, increase from 0 up to n.
  • The binomial coefficients in the expansion are arranged in an array, which is called Pascal's triangle. This pattern developed is summed up by the binomial theorem formula.