Question:

The coefficient of $x^2$ in the expansion of the product $(2-x^2)??(1+2x+3x^2)^6 + (1-4x^2)^6)$ is :

Updated On: Jul 29, 2022
  • 107
  • 106
  • 108
  • 155
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

coefficient of $x^2= 2$ coefficient of $x^2$ in $((1 + 2x + 3x^2)^6 + (1 - 4x^2)6)$ - constant term $(1 + 2x + 3x^2)6 \sum_\limits{r=0}^6$ $^{6}C_{r}\left(2x+3x^{2}\right)^{r}$ $=^{6}C_{0}+^{6}C_{1}\left(2x+3x^{2}\right)+^{6}C_{2} \left(2x+3x^{2}\right)^{2}+ ...$ coefficient of $x^2 = 2(18 + 60 - 24) - 2$ $= 108 - 2 = 106$
Was this answer helpful?
0
0

Concepts Used:

Binomial Expansion Formula

The binomial expansion formula involves binomial coefficients which are of the form 

(n/k)(or) nCk and it is calculated using the formula, nCk =n! / [(n - k)! k!]. The binomial expansion formula is also known as the binomial theorem. Here are the binomial expansion formulas.

This binomial expansion formula gives the expansion of (x + y)n where 'n' is a natural number. The expansion of (x + y)n has (n + 1) terms. This formula says:

We have (x + y)n = nC0 xn + nC1 xn-1 . y + nC2 xn-2 . y2 + … + nCn yn

General Term = Tr+1 = nCr xn-r . yr

  • General Term in (1 + x)n is nCr xr
  • In the binomial expansion of (x + y)n , the rth term from end is (n – r + 2)th .