Question:

The coefficient of performance of a refrigerator is $5$. If the temperature inside freezer is $-20^{\circ }C, $ the temperature of the surroundings to which it rejects heat is

Updated On: Jun 23, 2024
  • $11^{\circ }C$
  • $21^{\circ }C$
  • $31^{\circ }C$
  • $41^{\circ }C$
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The Correct Option is C

Solution and Explanation

The coefficient of performance of a refrigerator is
where $T_1 $ and $T_2 $ are the temperatures of hot and cold reservoirs (in kelvin) respectively.
Here, $\alpha =5 , \, T_2=-20^{\circ}C=-20+273\,K=253\, K $
$\, \, \, \, \, T_1=? $
$\therefore \, \, \, 5=\frac {253\,K}{T_1 -253\,K }$
$5T_1-5(253\,K)=253\,K $
$5T_1=253\,K+5(253\,K)=6(253\,K)$
$T_1= \frac {6}{5}(253 \,K)=303.6 \, K=303.6-273 $
$ =30.6^{\circ}C \approx 31^{\circ}C $
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Concepts Used:

Work Done Thermodynamics

In thermodynamics, work is a way of energy transfer from a system to surroundings, under the influence of external factors such gravity, electromagnetic forces, pressure/volume etc.

Energy (ΔU) can cross the boundary of a system in two forms -> Work (W) and Heat (q). Both work and heat refer to processes by which energy is transferred to or from a substance.

ΔU=W+q

Work done by a system is defined as the quantity of energy exchanged between a system and its surroundings. It is governed by external factors such as an external force, pressure or volume or change in temperature etc.

Work (W) in mechanics is displacement (d) against a resisting force (F).

Work has units of energy (Joule, J)