Question:

The circuit shown below uses an ideal OpAmp. Output \( V_o \) in volt is \(\underline{\hspace{2cm}}\) (rounded off to one decimal place). 

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In a non-inverting amplifier, the gain is determined by the ratio of the feedback resistor to the input resistor.
Updated On: Jan 8, 2026
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Correct Answer: 1

Solution and Explanation

The circuit is a non-inverting amplifier with a voltage divider formed by resistors \( 10 \, k\Omega \), \( 10 \, k\Omega \), and \( 1 \, k\Omega \). The closed-loop gain of the amplifier is given by: \[ A = 1 + \frac{R_f}{R_{\text{in}}} \] where \( R_f = 10 \, k\Omega \) and \( R_{\text{in}} = 1 \, k\Omega \). Thus: \[ A = 1 + \frac{10}{1} = 11 \] The output voltage is then: \[ V_o = A \times V_{\text{in}} = 11 \times 50 \, \text{mV} = 550 \, \text{mV} = 0.55 \, \text{V} \] Thus, the output \( V_o \) is \( 0.6 \, \text{V} \) (rounded off to one decimal place).
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