The given chemical equation is:
BaCl2 + Na2SO4 → BaSO4 + 2NaCl
In this reaction:
- Barium (Ba2+) from BaCl2 combines with SO42− from Na2SO4 to form BaSO4 (a precipitate).
- Sodium (Na+) and Cl− ions combine to form NaCl.
This is a classic example of a double-displacement reaction, where ions are exchanged between the reacting compounds.
The given chemical equation is: \[ \text{BaCl}_2 + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaCl} \] This is an example of a Double-displacement reaction. In a double-displacement reaction, the cations and anions of two reactants exchange places to form new products. In this case, the Ba2+ ion from BaCl2 combines with the SO42- ion from Na2SO4 to form BaSO4, and the Na+ ion from Na2SO4 combines with the Cl- ion from BaCl2 to form NaCl. Thus, the correct answer is Double-displacement.
\(\text{Reaction of aniline with conc. HNO}_3 \text{ and conc. H}_2\text{SO}_4 \text{ at 298 K will produce 47\% of:}\)