Step 1: Understanding Tollen’s Test Ammoniacal silver nitrate (\( AgNO_3 \)) is used in Tollen’s test to detect reducing sugars. A reducing sugar has a free aldehyde or ketone group that can reduce \( Ag^+ \) to metallic silver.
Step 2: Identifying Reducing and Non-Reducing Sugars - Sucrose is a non-reducing sugar because its glycosidic bond prevents the free aldehyde or ketone group from participating in the reaction. - Maltose, lactose, and fructose are reducing sugars, which means they react with ammoniacal \( AgNO_3 \).
Step 3: Conclusion Since sucrose does not react with Tollen’s reagent, it is the correct answer.
Given below are some nitrogen containing compounds:
Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume ...... mg of HCl.
(Given Molar mass in g mol\(^{-1}\): C = 12, H = 1, O = 16, Cl = 35.5.)

Given below are some nitrogen containing compounds:
Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume ...... mg of HCl.
(Given Molar mass in g mol\(^{-1}\): C = 12, H = 1, O = 16, Cl = 35.5.)

Match the following with their pKa values 
At T(K), the value of \( K_c \) for the reaction
\[ AO_2(g) + BO_2(g) \leftrightarrow{} AO_3(g) + BO(g) \] is 16. In a one-litre closed flask, 1 mole each of \( AO_2(g) \), \( BO_2(g) \), \( AO(g) \), and \( BO(g) \) were taken and heated to T(K).
What are the equilibrium concentrations (in mol L\(^{-1}\)) of \( BO_2(g) \) and \( BO(g) \) respectively?
At equilibrium for the reaction $ A_2 (g) + B_2 (g) \rightleftharpoons 2AB (g) $, the concentrations of $ A_2 $, $ B_2 $, and $ AB $ respectively are $ 1.5 \times 10^{-3} M $, $ 2.1 \times 10^{-3} M $, and $ 1.4 \times 10^{-3} M $. What will be $ K_p $ for the decomposition of $ AB $ at the same temperature?
The molar heats of fusion and vaporization of benzene are 10.9 and 31.0 kJ mol\(^{-1}\) respectively. The changes in entropy for the solid \(\rightarrow\) liquid and liquid \(\rightarrow\) vapor transitions for benzene are \(x\) and \(y\) J K\(^{-1}\) mol\(^{-1}\) respectively. The value of \(y(x)\) in J\(^2\) K\(^{-2}\) mol\(^{-2}\) is: