Question:

The capacitance of an isolated sphere of radius \( r_1 \) is increased by 5 times when enclosed by an earthed concentric sphere of radius \( r_2 \). The ratio \( \frac{r_1}{r_2} \) is:

Show Hint

For concentric spherical capacitors, the capacitance increases when the outer sphere is grounded. Use \( C_2 = \frac{4 \pi \varepsilon_0 r_1 r_2}{r_2 - r_1} \) to find the ratio.
Updated On: Mar 24, 2025
  • \( \frac{4}{5} \)
  • \( \frac{5}{4} \)
  • \( \frac{5}{1} \)
  • \( \frac{1}{5} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Apply Capacitance Formula for Concentric Spheres The capacitance of an isolated sphere is: \[ C_1 = 4 \pi \varepsilon_0 r_1 \] When enclosed by a conducting sphere at radius \( r_2 \), the new capacitance is: \[ C_2 = \frac{4 \pi \varepsilon_0 r_1 r_2}{r_2 - r_1} \] Given that \( C_2 = 5C_1 \), we get: \[ \frac{r_1 r_2}{r_2 - r_1} = 5 r_1 \] Step 2: Solve for \( \frac{r_1}{r_2} \) \[ \frac{r_1}{r_2} = \frac{4}{5} \] Thus, the correct answer is \( \frac{4}{5} \).
Was this answer helpful?
0
0

Top Questions on Electrostatics

View More Questions