Step 1: Simplify the expression.
Given expression:
\[
\overline{P}(\overline{P} + Q)(Q + \overline{Q})
\]
Since \(Q + \overline{Q} = 1\), the expression simplifies to
\[
\overline{P}(\overline{P} + Q)
\]
Step 2: Apply absorption law.
\[
\overline{P}(\overline{P} + Q) = \overline{P}
\]
since \(\overline{P}\) multiplied by anything containing \(\overline{P}\) results in \(\overline{P}\).
Step 3: Conclusion.
Hence, the Boolean function is equivalent to \(\overline{P}\).
Match the LIST-I with LIST-II
| LIST-I (Logic Gates) | LIST-II (Expressions) | ||
|---|---|---|---|
| A. | EX-OR | I. | \( A\bar{B} + \bar{A}B \) |
| B. | NAND | II. | \( A + B \) |
| C. | OR | III. | \( AB \) |
| D. | EX-NOR | IV. | \( \bar{A}\bar{B} + AB \) |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Counters) | List-II (Delay/Number of States) |
|---|---|
| (A) n-bit ring counter | (I) Number of states is \( 2^n \) |
| (B) MOD-\(2^n\) asynchronous counter | (II) Fastest counter |
| (C) n-bit Johnson counter | (III) Number of used states is \( n \) |
| (D) Synchronous counter | (IV) Number of used states is \( 2n \) |
Choose the correct answer from the options given below:
A MOD 2 and a MOD 5 up-counter when cascaded together results in a MOD ______ counter.

At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)