\((~(p ∧q)) ∨q \)is equivalent to :
The following is the truth table
| p | q | p ∧ q | ~p ∧ q | (~(p ∧ q)) ∨ q | p ∨ q | p → q | p → (p ∨ q) |
|---|---|---|---|---|---|---|---|
| T | T | T | F | T | T | T | T |
| T | F | F | T | T | T | F | T |
| F | T | F | T | T | T | T | T |
| F | F | F | T | T | F | T | T |
| Tautology | Tautology |
Hence, \((∼(p∧q)) ∨ q ≡ p → (p ∨ q) \)
Hence, the correct option is (D): \(p→ (p∨q)\)
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
A System of Linear Inequalities is a set of 2 or more linear inequalities which have the same variables.
Example
\(x + y ≥ 5\)
\(x – y ≤ 3\)
Here are two inequalities having two same variables that are, x and y.
The solution of a system of a linear inequality is the ordered pair which is the solution of all inequalities in the studied system and the graph of the system of a linear inequality is the graph of the common solution of the system.
Therefore, the Solution of the System of Linear Inequalities could be:
For the Solution of the System of Linear Inequalities, the Graphical Method is the easiest method. In this method, the process of making a graph is entirely similar to the graph of linear inequalities in two variables.
In the Non-Graphical Method, there is no need to make a graph but we can find the solution to the system of inequalities by finding the interval at which the system persuades all the inequalities.
In this method, we have to find the point of intersection of the two inequalities by resolving them. It could be feasible that there is no intersection point between them.