Question:
The bond angles of \( \text{NH}_3 \), \( \text{NH}_2 \), and \( \text{NH}_4^+ \) are?
The bond angles of \( \text{NH}_3 \), \( \text{NH}_2 \), and \( \text{NH}_4^+ \) are?
Show Hint
The bond angles in molecules depend on the hybridization and the number of bonding and lone pairs on the central atom.
Updated On: Jan 12, 2026
- 107°, 115°, 120°
- 90°, 109°, 120°
- 104°, 118°, 120°
- 120°, 120°, 109°
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The bond angles in these molecules are influenced by the electron pair geometry around the central atom. \( \text{NH}_3 \) has a 107° bond angle, \( \text{NH}_2 \) has a slightly larger bond angle, and \( \text{NH}_4^+ \) has a 120° bond angle due to its tetrahedral geometry.
Was this answer helpful?
0
0
Top Questions on Chemical bonding and molecular structure
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are :
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- The wave numbers of three spectral lines of hydrogen atom are considered. Identify the set of spectral lines belonging to the {Balmer series. (\(R\) = Rydberg constant)}
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- Consider the reaction: \[ \text{Ph–CH=CH}_2 \xrightarrow[\text{peroxide}]{\text{HBr}} \text{Product} \] Which of the following statements are correct?
[A.] The reaction proceeds through a more stable radical intermediate.
[B.] The role of peroxide is to generate \(\mathrm{H^\bullet}\) radical.
[C.] During this reaction, benzene is formed as a byproduct.
[D.] \(1\)-Bromo-\(2\)-phenylethane is formed as a minor product.
[E.] The same reaction in absence of peroxide proceeds via a carbocation intermediate. Choose the correct answer.- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is :
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- Given below are two statements :
Statement I : The correct order in terms of bond dissociation enthalpy is \( Cl_2>Br_2>F_2>I_2 \).
Statement II : The correct trend in the covalent character of the metal halides is \( SnCl_2>SnCl_4 \), \( PbCl_2>PbCl_4 \) and \( UF_4>UF_6 \).
In the light of the above statements, choose the correct answer from the options given below :- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
View More Questions
Questions Asked in VITEEE exam
- Find the value of \( x \) in the following equation: \[ \frac{2}{x} + \frac{3}{x + 1} = 1 \]
- VITEEE - 2025
- Algebra
- How many numbers between 0 and 9 look the same when observed in a mirror?
- VITEEE - 2025
- Odd one Out
- In a code language, 'TIGER' is written as 'JUISF'. How will 'EQUAL' be written in that language?
- VITEEE - 2025
- Odd one Out
- In a code language, 'TIGER' is written as 'JUISF'. How will 'EQUAL' be written in that language?
- VITEEE - 2025
- Data Interpretation
- TUV : VYB :: PRA : ?
- VITEEE - 2025
- Odd one Out
View More Questions