In the H$_2$O (water) molecule, the oxygen atom forms two single bonds with hydrogen atoms and has two lone pairs of electrons. This leads to a bent or V-shaped molecular geometry, not linear or trigonal planar. Due to the repulsion from lone pairs, the bond angle is reduced from the ideal tetrahedral angle (109$^\circ$ 28') to approximately 104$^\circ$ 31'. This value is experimentally determined and is a characteristic property of the water molecule's shape.
The correct option is (D): \(104° 31’\)
Identify the correct orders against the property mentioned:
A. H$_2$O $>$ NH$_3$ $>$ CHCl$_3$ - dipole moment
B. XeF$_4$ $>$ XeO$_3$ $>$ XeF$_2$ - number of lone pairs on central atom
C. O–H $>$ C–H $>$ N–O - bond length
D. N$_2$>O$_2$>H$_2$ - bond enthalpy
Choose the correct answer from the options given below: