In the H$_2$O (water) molecule, the oxygen atom forms two single bonds with hydrogen atoms and has two lone pairs of electrons. This leads to a bent or V-shaped molecular geometry, not linear or trigonal planar. Due to the repulsion from lone pairs, the bond angle is reduced from the ideal tetrahedral angle (109$^\circ$ 28') to approximately 104$^\circ$ 31'. This value is experimentally determined and is a characteristic property of the water molecule's shape.
The correct option is (D): \(104° 31’\)