Question:
The bleaching action of chlorine is due to the liberation of the following
The bleaching action of chlorine is due to the liberation of the following
Updated On: Jun 3, 2024
- $ HOCl $
- $ HCl $
- $ [O] $
- $O_{2}$
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The Correct Option is C
Solution and Explanation
Chlorine reacts slowly with $H _{2} O$ to form $HCl$ and $HOCl$.
The $HOCl$. then decomposes into $HOCl$. and $[O]$ radicals.
$Cl _{2}+ H _{2} O \rightleftharpoons HCl + HOCl$
These oxygen radicals are very strong oxidising as well as effective bleaching agent in aqueous solution of $Cl _{2}$ or hypochlorite salt.
The $HOCl$. then decomposes into $HOCl$. and $[O]$ radicals.
$Cl _{2}+ H _{2} O \rightleftharpoons HCl + HOCl$
These oxygen radicals are very strong oxidising as well as effective bleaching agent in aqueous solution of $Cl _{2}$ or hypochlorite salt.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
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- Group 16 Elements: Oxygen family
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- Group 18 Elements: Neon family