The correct answer is (C):
Given, the non-parallel sides are equal.
Let the non-parallel sides be x cm each
x = √122+52 = 13
So, we have 6 faces, two are trapezoid faces and 4 are rectangular faces.
Area of 2 trapeziums
= 2[1/2(12)(10+20)]=360cm2
Area of 4 rectangles
= 2[13 × 20] + 20(20) + 10(20) = 1120 cm2
Total area = 1120 + 360 = 1480 cm2
The center of a circle $ C $ is at the center of the ellipse $ E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 $, where $ a>b $. Let $ C $ pass through the foci $ F_1 $ and $ F_2 $ of $ E $ such that the circle $ C $ and the ellipse $ E $ intersect at four points. Let $ P $ be one of these four points. If the area of the triangle $ PF_1F_2 $ is 30 and the length of the major axis of $ E $ is 17, then the distance between the foci of $ E $ is: