Question:
The average of 5 consecutive positive integers starting with m is n. What is the average of 6 consecutive positive integers starting with (m+2)?
The average of 5 consecutive positive integers starting with m is n. What is the average of 6 consecutive positive integers starting with (m+2)?
Updated On: Jul 4, 2024
- \(\frac{2n+5}{2}\)
- n+2
- n+3
- \(\frac{2n+9}{2}\)
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The Correct Option is A
Solution and Explanation
The correct answer is(A): \(\frac{2n+5}{2}\)
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