Question:

The average of 5 consecutive positive integers starting with m is n. What is the average of 6 consecutive positive integers starting with (m+2)?

Updated On: Jul 4, 2024
  • 2n+52\frac{2n+5}{2}
  • n+2
  • n+3
  • 2n+92\frac{2n+9}{2}
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The correct answer is(A): 2n+52\frac{2n+5}{2}
Was this answer helpful?
0
0

Top Questions on Average

View More Questions