Question:
The atomic numbers of Cr and Fe are respectively 24 and 26, which of the following is paramagnetic with the spin of the electron :
The atomic numbers of Cr and Fe are respectively 24 and 26, which of the following is paramagnetic with the spin of the electron :
Updated On: Apr 21, 2025
[Cr(CO)6]
[Fe(CO)5]
[Fe(CN)6]–4
[Cr(NH3)6]+3
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The correct option is (D) : [Cr(NH3)6]+3
Out of CO, CN −and NH3, increasing field strength is NH3<CN−<CO Cr has 24 electrons, Fe→26 electrons. Fe2+ has 24 electrons and Cr+3 has 21 electrons. The 4 unpaired electrons in Cr and Fe can pair up because of the strong field ligand CO . CN−also strong field ligand. So, 4 electrons in Fe2+ also pair up. Though NH3 is a strong field ligand, only one electron remains in Cr+3.So no case of pairing here and [Cr(NH3)6]3+ is paramagnetic.
Out of CO, CN −and NH3, increasing field strength is NH3<CN−<CO Cr has 24 electrons, Fe→26 electrons. Fe2+ has 24 electrons and Cr+3 has 21 electrons. The 4 unpaired electrons in Cr and Fe can pair up because of the strong field ligand CO . CN−also strong field ligand. So, 4 electrons in Fe2+ also pair up. Though NH3 is a strong field ligand, only one electron remains in Cr+3.So no case of pairing here and [Cr(NH3)6]3+ is paramagnetic.
Was this answer helpful?
0
0
Top Questions on coordination compounds
- Calculate the empirical formula of a compound containing 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass.
- BITSAT - 2025
- Chemistry
- coordination compounds
- The complex $[Cr(NH_3)_4Cl_2]^+$ shows how many geometrical isomers?
- BITSAT - 2025
- Chemistry
- coordination compounds
- The number of paramagnetic complexes among $[FeF_6]^{3-}, [Fe(CN)_6]^{3-}, [Mn(CN)_6]^{3-}, [Co(C_2O_4)_3]^{3-}, [MnCl_6]^{3-}$ and $[CoF_6]^{3-}$, which involved $d^2sp^3$ hybridization is ...............
- JEE Main - 2025
- Chemistry
- coordination compounds
- An octahedral complex having molecular composition Co.5NH$_3$.Cl.SO$_4$ has two isomers A and B. The solution of A gives a white precipitate with AgNO$_3$ solution and the solution of B gives a white precipitate with BaCl$_2$ solution. The type of isomerism exhibited by the complex is,
- JEE Main - 2025
- Chemistry
- coordination compounds
- Write the IUPAC name of complex compound \( K_3[Cr(C_2O_4)_3] \).
- Bihar Board XII - 2025
- Chemistry
- coordination compounds
View More Questions
Questions Asked in NEET exam
- A wire of resistance \(R\) is cut into 8 equal pieces. From these pieces, two equivalent resistances are made by adding four of these together in parallel. Then these two are added in series. The net effective resistance of the combination is:
- NEET (UG) - 2025
- Resistance
- Which of the following organisms cannot fix nitrogen? A. Azotobacter
B. Oscillatoria
C. Anabaena
D. Volvox
E. Nostoc
Choose the correct answer from the options given below:- NEET (UG) - 2025
- Nitrogen Fixation
- Which of the following are paramagnetic?
A. [NiCl$_4$]$^{2-}$
B. Ni(CO)$_4$
C. [Ni(CN)$_4$]$^{2-}$
D. [Ni(H$_2$O)$_6$]$^{2+}$
E. Ni(PPh$_3$)$_4$
Choose the correct answer from the options given below:- NEET (UG) - 2025
- Coordination chemistry
Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): A typical unfertilized, angiosperm embryo sac at maturity is 8-nucleate and 7-celled.
Reason (R): The egg apparatus has 2 polar nuclei.In the light of the above statements, choose the correct answer from the options given below:
- NEET (UG) - 2025
- Angiosperms
- A ball of mass 0.5 kg is dropped from a height of 10 m. The ball hits the ground and rises to a height of 1.5 m. The impulse imparted to the ball during its collision with the ground is : (Take \(g = 9.8 \, \text{m/s}^2\))
- NEET (UG) - 2025
- Collision and Impulse
View More Questions
Concepts Used:
Nomenclature of Coordination Compounds
Nomenclature of Coordination Compounds is important in Coordination Chemistry because of the need to have an unambiguous method of describing formulas and writing systematic names, particularly when dealing with isomers.
We can apply the following formulas:
- On the very first the central atom is listed.
- Ligands are then listed in alphabetical order and their placement in the list does not depend on their charge.
- Polydentate ligands are also listed alphabetically. In such a case of an abbreviated ligand, the first letter of the abbreviation is used to determine the position of the ligand in alphabetical order.
- The formula for the entire coordination entity is enclosed in square brackets whether charged or not. The formulas are enclosed in parentheses when ligands are polyatomic. Ligand abbreviations are also enclosed in parentheses.
- Within a coordination sphere, there should be no space between the ligands and the metal.
- When the formula of a charged coordination entity is to be written without that of the counter-ions, the charge is indicated outside the square brackets as a right superscript with the number before the sign. For example, [Co(CN)6]3-, [Cr(H2O)6]3+, etc.
- The charge of the anion(s) balances the charge of the cation(s).