Question:

The arithmetic mean of \( a, b, c, d \) is 14.
Quantity A: 32
Quantity B: The arithmetic mean of \( a + b \), \( c + d \), and \( a - b + c - d = 48 \)

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When given the arithmetic mean, use the sum of the numbers and divide by the number of terms to find the mean.
Updated On: Sep 30, 2025
  • Quantity A and Quantity B are equal.
  • Quantity A is greater.
  • Quantity B is greater.
  • The relationship between Quantity A and Quantity B cannot be determined.
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The Correct Option is C

Solution and Explanation

Step 1: Given the arithmetic mean of \( a, b, c, d \). The arithmetic mean of \( a, b, c, d \) is given by: \[ \frac{a + b + c + d}{4} = 14 \Rightarrow a + b + c + d = 56. \]
Step 2: Work with the second condition. We are asked for the arithmetic mean of the quantities \( a + b \), \( c + d \), and \( a - b + c - d \). We have: \[ a + b + c + d = 56 \quad \text{and} \quad a - b + c - d = 48. \] Thus, the arithmetic mean is: \[ \frac{56 + 48}{3} = 34.67. \]
Step 3: Conclusion. So, Quantity B is greater than Quantity A.
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