Step 1: To find the area between the curve and the lines, we need to set up an integral. The equation of the curve is \( x = 2y + 3 \). The bounds for \( y \) are from \( y = -1 \) to \( y = 1 \).
Step 2: The area is given by:
\[
\int_{-1}^{1} (2y + 3) \, dy.
\]
Step 3: Solving the integral, we get an area of 6 sq. units.
Final Answer:
\[
\boxed{6 \, \text{sq. units}}
\]