Question

The area of cross section of the rope used to lift a load by a crane is \(2.5 × 10^{–4}\) \(m^2\). The maximum lifting capacity of the crane is \(10\) metric tons. To increase the lifting capacity of the crane to \(25\) metric tons, The required area of cross section of the rope should be

• A. \(6.25 × 10^{–4} \;m^2\)
• B. \(10 × 10^{–4} \;m^2\)
• C. \(1 × 10^{–4}\; m^2\)
• D. \(1.67 × 10^{–4}\; m^2\)

Answer 1

The Correct Option is A

area of cross section of the rope : 

= \(\frac{25}{10} \times 2.5 \times 10 ^{-4} \;\bigg[ A_2 = \frac{W_2}{W_1} A_1\bigg]\)

= \(6.25 \times 10 ^{-4}\; m^2\)