Question:
The area of a triangle with vertices (a, b+c), (b, c+a) and (c, a+b) is
The area of a triangle with vertices (a, b+c), (b, c+a) and (c, a+b) is
Updated On: May 17, 2024
- \(\frac{1}{2}abc\)
- \(\frac{1}{2}(ab+bc+ca)\)
- \(\frac{1}{2}(ab^2+b^2+c^2)\)
- 0
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The Correct Option is D
Solution and Explanation
The correct option is (D): 0
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