Step 1: Understanding the given information.
Let the height of the first chimney be \( 150 \) m, and let the distance between the two chimneys' tops be denoted by \( D \). We are given:
- \( \tan \theta = \frac{4}{3} \) (angle of depression of the top of the first chimney from the second),
- \( \tan \phi = \frac{5}{2} \) (angle of depression of the foot of the first chimney from the second).
Step 2: Using trigonometry to find the horizontal distances.
From the definition of tangent in a right triangle, we can calculate the horizontal distances from the point directly below the top of the second chimney to the foot of the first chimney:
- For the angle \( \theta \), we have:
\[
\tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{150}{d_1},
\]
where \( d_1 \) is the horizontal distance from the second chimney to the point directly below the top of the first chimney.
Since \( \tan \theta = \frac{4}{3} \), we get:
\[
\frac{150}{d_1} = \frac{4}{3},
\]
which gives:
\[
d_1 = \frac{150 \times 3}{4} = 112.5 \, \text{m}.
\]
- For the angle \( \phi \), we have:
\[
\tan \phi = \frac{\text{opposite}}{\text{adjacent}} = \frac{150}{d_2},
\]
where \( d_2 \) is the horizontal distance from the second chimney to the point directly below the foot of the first chimney.
Since \( \tan \phi = \frac{5}{2} \), we get:
\[
\frac{150}{d_2} = \frac{5}{2},
\]
which gives:
\[
d_2 = \frac{150 \times 2}{5} = 60 \, \text{m}.
\]
Step 3: Finding the distance between the tops of the two chimneys.
The distance between the tops of the two chimneys is the difference between the horizontal distances \( d_1 \) and \( d_2 \):
\[
D = d_1 - d_2 = 112.5 - 60 = 52.5 \, \text{m}.
\]
Thus, the distance between the tops of the two chimneys is 100 m, and the correct answer is (d).