Question:

The angle between the linear momentum and angular momentum of a particle moving along a circle is

Updated On: Jun 2, 2024
  • $ 0^{\circ} $
  • $ 45^{\circ} $
  • $ 90^{\circ} $
  • $ 180^{\circ} $
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The Correct Option is C

Solution and Explanation

The angular momentum of a particle moving along a circle of radius $r$ is
$\vec{L}=\vec{r}\times\vec{p}$ where $\vec{p}$ is the linear momentum of the particle
By the definition of vector product, $\vec{L}$ is perpendicular to $\vec{p}$.
So the angle between them is $90^{\circ}$.
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Concepts Used:

Center of Mass

The center of mass of a body or system of a particle is defined as a point where the whole of the mass of the body or all the masses of a set of particles appeared to be concentrated.

The formula for the Centre of Mass:

Center of Gravity

The imaginary point through which on an object or a system, the force of Gravity is acted upon is known as the Centre of Gravity of that system. Usually, it is assumed while doing mechanical problems that the gravitational field is uniform which means that the Centre of Gravity and the Centre of Mass is at the same position.