Column J | Column K | ||
---|---|---|---|
P | i | 132 | |
Q | ii | 110 | |
R | iii | 95 | |
S | iv | 88 |
P – iii, Q – iv, R – ii, S – i
P – i, Q – ii, R – iii, S – iv
P – iii, Q – ii, R – i, S – iv
P – ii, Q – i, R – iv, S – iii
Order of stability of free radical
∴ Order of bond energy :
Initiation step is exothermic with H° = –58 kcal mol–1
Propagation step involving ·CH3 formation is exothermic with H° = –2 kcal mol–1
Propagation step involving CH3Cl formation is endothermic with H° = +27 kcal mol–1
The reaction is exothermic with H° = –25 kcal mol–1
Step (1) → Endothermic (bond breaking)
Step (2) → ∆H = 105 – 103 = 2 kcal/mol (Endothermic)
Step (3) → ∆H = 58 – 85 = –27 kcal/mol (Exothermic)
For complete reaction
∆H = 58 + 105 – 85 – 103
= –25 kcal/mol
Match the LIST-I with LIST-II:
Choose the correct answer from the options given below :
The number of molecules/ions that show linear geometry among the following is _____. SO₂, BeCl₂, CO₂, N₃⁻, NO₂, F₂O, XeF₂, NO₂⁺, I₃⁻, O₃