Let’s assign variables to the daily earnings of Neeta, Geeta, and Sita: \( N \), \( G \), and \( S \) respectively.
\[ N + G = 6S \quad \Rightarrow \quad N = 6S - G \quad \text{......(i)} \]
Substituting the value of \( N \) from equation (i) into the second equation \( S + N = 2G \), we get: \[ S + 6S - G = 2G \] Combining like terms: \[ 7S = 3G \] \[ G = \frac{7}{3} S \quad \text{......(ii)} \]
Substituting \( G = \frac{7}{3} S \) from equation (ii) into equation (i): \[ N = 6S - \frac{7}{3} S = \frac{18}{3} S - \frac{7}{3} S = \frac{11}{3} S \quad \text{......(iii)} \]
The earnings ratio is: \[ N : G : S = \frac{11}{3} S : \frac{7}{3} S : S \] This simplifies to: \[ N : G : S = 11S : 7S : 3S \]
Clearly, Neeta earns the most and Sita earns the least. Therefore, the ratio of the daily earnings of the one who earns the most to the one who earns the least is: \[ 11S : 3S = 11 : 3 \]
The correct option is \( \boxed{(B): 11 : 3} \).
Let the daily earnings be:
Given equations:
\[ n + g = 6s \quad (i) \] \[ s + n = 2g \quad (ii) \]
\[ (s + n) - (n + g) = 2g - 6s \implies s - g = 2g - 6s \]
\[ s - g = 2g - 6s \implies 7s = 3g \implies s = \frac{3}{7} g \]
\[ g = 7a, \quad s = 3a \]
\[ n + g = 6s \implies n + 7a = 18a \implies n = 11 a \]
\[ n : s = 11a : 3a = \boxed{11 : 3} \]
The ratio of earnings between Neeta and Sita is 11 : 3.
When $10^{100}$ is divided by 7, the remainder is ?