Question:

The activity of a radioactive sample is measured as \( N_0 \) counts per minute at \( t = 0 \) and \( N \) counts per minute at \( t = 5 \) min. The time, in minutes, at which the activity reduces to half its value is?

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The time for a radioactive sample to decay to half its activity is its half-life, which can be calculated from the decay constant.
Updated On: Jan 12, 2026
  • \( \log_2 5 \)
  • \( \log_2 2 \)
  • \( 5 \log_2 2 \)
  • \( 5 \log_2 5 \)
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The Correct Option is C

Solution and Explanation

The time at which the activity halves is determined by the half-life of the substance. Using the decay law, the time can be calculated based on the logarithmic relationship between the initial and reduced activity.
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